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360=2x^2+6x
We move all terms to the left:
360-(2x^2+6x)=0
We get rid of parentheses
-2x^2-6x+360=0
a = -2; b = -6; c = +360;
Δ = b2-4ac
Δ = -62-4·(-2)·360
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-54}{2*-2}=\frac{-48}{-4} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+54}{2*-2}=\frac{60}{-4} =-15 $
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